At a local high school, GPA's are normally distributed with a mean of 2.5 and standard deviation of 0.6. What percentage of students at the high school have a GPA higher than 3.0?
P(X>3.0)=P(Z>3.0−2.50.6)=P(Z>0.83)=1−P(Z<0.83)=P(X>3.0)=P(Z>\frac{3.0-2.5}{0.6})=P(Z>0.83)=1-P(Z<0.83)=P(X>3.0)=P(Z>0.63.0−2.5)=P(Z>0.83)=1−P(Z<0.83)=
=1−0.7967=0.2033=20.33%.=1-0.7967=0.2033=20.33\%.=1−0.7967=0.2033=20.33%.
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