Question #249500

Sam has 6 rose bushes. He counted the flowers on each of them. There are 8, 2, 5, 4, 11 and 9. Find the Standard Deviation. Is X a “Usual” number of flowers? X is your last two digits of your CUNYFirst ID Number. (00 = 0, 01 = 1, …) (20 points) my id is 03


Expert's answer

mean=xˉ=8+2+5+4+11+96=6.5mean=\bar{x}=\dfrac{8+2+5+4+11+9}{6}=6.5

Var(x)=σ2=16((8−6.5)2+(2−6.5)2Var(x)=\sigma^2=\dfrac{1}{6}((8-6.5)^2+(2-6.5)^2

+(5−6.5)2+(4−6.5)2+(11−6.5)2+(9−6.5)2)+(5-6.5)^2+(4-6.5)^2+(11-6.5)^2+(9-6.5)^2)

=57.56≈9.583333=\dfrac{57.5}{6}\approx9.583333

σ=σ2=57.56≈3.0957\sigma=\sqrt{\sigma^2}=\sqrt{\dfrac{57.5}{6}}\approx3.0957

μ−σ=6.5−57.56≈3.4043\mu-\sigma=6.5-\sqrt{\dfrac{57.5}{6}}\approx3.4043

μ+σ=6.5+57.56≈9.5957\mu+\sigma=6.5+\sqrt{\dfrac{57.5}{6}}\approx9.5957

By 68–95–99.7 rule

P(μ−2σ≤x≤μ+2σ)=0.9545P(\mu-2\sigma\leq x\leq \mu+2\sigma)=0.9545

μ−2σ=6.5−2(57.56)≈0.3086\mu-2\sigma=6.5-2(\sqrt{\dfrac{57.5}{6}})\approx0.3086

μ+2σ=6.5+2(57.56)≈12.6914\mu+2\sigma=6.5+2(\sqrt{\dfrac{57.5}{6}})\approx12.6914

33 is within [μ−2σ,μ+2σ].[\mu-2\sigma, \mu+2\sigma]. Then  X=3X=3 is a “Usual” number of flowers.


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