p=0.35n=40q=p−1=0.65P(X=x)=Cxnpxqn−xa)P(X≤15)=∑x=015Cx40(0.35)x(0.65)40−xP(X≤15)=0.6946b)P(12<X<18)=∑1317Cx40(0.35)x(0.65)40−x=∑x=017Cx40(0.35)x(0.65)40−x−∑x=012Cx40(0.35)x(0.65)40−x=0.8761−0.3143=0.5618c)Mean=np=40×0.35=14P(X=14)=C1440(0.35)14(0.65)26P(X=14)=0.1313
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