Answer to Question #244353 in Statistics and Probability for Flyyboyy

Question #244353
In a particular country on the African continent, 35% of the population is estimated to have at
at least one smart phone. If a small sample of 40 people is selected from the population
for a statistical investigation, Use the Binomial distribution to estimate the probability that,
the number of people in the sample that have at least one smart phone is;
a) at most 15;
b) more than 12 but fewer than 18;
c) exactly equal to the mean of the distribution
1
Expert's answer
2021-09-30T15:39:13-0400

p=0.35n=40q=p1=0.65P(X=x)=Cxnpxqnxa)  P(X15)=x=015Cx40(0.35)x(0.65)40xP(X15)=0.6946b)  P(12<X<18)=1317Cx40(0.35)x(0.65)40x=x=017Cx40(0.35)x(0.65)40xx=012Cx40(0.35)x(0.65)40x=0.87610.3143=0.5618c)  Mean=np=40×0.35=14P(X=14)=C1440(0.35)14(0.65)26P(X=14)=0.1313p=0.35 \\ n=40 \\ q=p-1 = 0.65 \\ P(X=x) = C^n_x p^x q^{n-x} \\ a) \; P(X≤15) = \sum^{15}_{x=0} C^{40}_x (0.35)^x (0.65)^{40-x} \\ P(X≤15) = 0.6946 \\ b) \; P(12<X<18) = \sum^{17}_{13} C^{40}_x (0.35)^x (0.65)^{40-x} \\ = \sum^{17}_{x=0} C^{40}_x (0.35)^x (0.65)^{40-x} - \sum^{12}_{x=0} C^{40}_x (0.35)^x (0.65)^{40-x} \\ = 0.8761-0.3143 \\ = 0.5618 \\ c) \; Mean = np = 40 \times 0.35 = 14 \\ P(X=14) = C^{40}_{14} (0.35)^{14} (0.65)^{26} \\ P(X=14) = 0.1313


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