A random sample of 64 bags of white cheddar popcorn weighed, on avarage, 5.23 ounces with a standard deviation of 0.24 ounces. Test the hypothesis that mean = 5.5 ounces against the alternative hypothesis, mean < 5.5 ounces at the 0.05 level of significance.
"n=64 \\\\\n\n\\bar{x}=5.23 \\\\\n\ns= 0.24 \\\\\n\nH_0: \\mu = 5.5 \\\\\n\nH_1: \\mu <5.5"
Test-statistic:
"t = \\frac{\\bar{x}- \\mu}{s \/ sqrt{n}} \\\\\n\nt = \\frac{5.23-5.5}{0.24 \/ \\sqrt{64}} = -9 \\\\\n\n\u03b1=0.05"
Critical value "t_{n-1, \u03b1} = t_{63,0.05}= -1.6694"
Since "|t| > t_{n-1, \u03b1}" we reject H0 and conclude, that "\\mu <5.5" at 0.05 level of significance.
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