Question #242013

Write the null and alternative hypothesis of given problem: ( 10 points)


    1. It is claimed that the average weight of a bag of biscuit is 250 grams with a standard deviation of 20.5 grams. Would you agree to this claim if a random sample of 50 bags of biscuits showed an average weight of 240 grams, using a 5% level of significance.



1
Expert's answer
2021-09-28T23:52:46-0400

The following null and alternative hypotheses need to be tested:

H0:μ=250H_0:\mu=250

H1:μ250H_1:\mu\not=250

This corresponds to a two-tailed test, for which a z-test for one mean, with known population standard deviation will be used.

Based on the information provided, the significance level is α=0.05,\alpha = 0.05, and the critical value for a two-tailed test is zc=1.96.z_c = 1.96.

The rejection region for this two-tailed test is R={z:z>1.96}.R = \{z: |z| > 1.96\}.

The z-statistic is computed as follows:


z=xˉμσ/n=24025020.5/503.4493z=\dfrac{\bar{x}-\mu}{\sigma/\sqrt{n}}=\dfrac{240-250}{20.5/\sqrt{50}}\approx-3.4493

Since it is observed that z=3.449>1.96=zc,|z| = 3.449 > 1.96=z_c, it is then concluded that the null hypothesis is rejected.

Using the P-value approach:

The p-value is p=2P(Z<3.4493)0.000562,p=2P(Z<-3.4493)\approx0.000562, and since p=0.0006<0.05=α,p=0.0006<0.05=\alpha, it is concluded that the null hypothesis is rejected.

Therefore, there is enough evidence to claim that the population mean μ\mu is different than 250,250, at the α=0.05\alpha = 0.05 significance level.




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