Question #241923

et X and Y be continuous random variables having joint density functio


1
Expert's answer
2021-09-28T20:38:10-0400

To find the constant c, we write

1=fXY(x,y)dxdy1=0101xcx+1dydx1=01(cx+1)(1x)dx1=12+16c.1=∫^∞_{−∞}∫^∞_{−∞}f_{XY}(x,y)dxdy\\ 1=∫^1_0∫^{1−x}_0cx+1dydx\\ 1=∫^1_0(cx+1)(1−x)dx\\ 1=\frac{1}{2}+\frac{1}{6}c.

Thus, we conclude c=3


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