Answer to Question #235292 in Statistics and Probability for May

Question

Consider the following case. Of 200 people in a survey, 120 are men and 80 are women. Of the 120 men, 40 own stock in a US corporation, while of the 80 women, 20 are stockholders. Determine the probability of selecting one person at random who is a man and owns stock.

Answer 1

$P_{Men}= \frac{120}{200}=\frac{3}{5}\\ P_{Women}= \frac{80}{200}=\frac{2}{5}\\ P_{Men \space with \space stock}= \frac{40}{120}=\frac{1}{3}\\ P_{Women \space with \space stock}= \frac{20}{80}=\frac{1}{4}\\$

Selecting one person at random who is a man and owns stock

$P=\frac{3}{5}* \frac{1}{3}= \frac{1}{5}$