What is the approximate percentage of healthy adults with body temperatures between 97.12° And 99.32
QUESTION
The body temperatures of a group of healthy adults have a bell-shaped distribution with a mean of 98.370F and a standard deviation of 0.490F. Using the empirical rule, find each approximate percentage below.
a) What is the approximate percentage of healthy adults with body temperatures within 2 standard deviations of the mean, or between 97.390F and 99.350F?
b) What is the approximate percentage of healthy adults with body temperatures between 97.880F and 98.860F?
SOLUTION
Step-by-step explanation:
Mean = 98.37
Standard deviation = 0.49
Empirical rule
1 ) 68% of the information lies within 1 standard deviation of mean
like 68% of information lies between: "\\mu" - "\\sigma" to "\\mu" + "\\sigma"
So, On the available information
98.37 - 0.49 to 98.37 + 0.49
97.88 to 98.86
So, 68% of information lies between 97.880F to 98.860F.
2) 95% of the information lies within 2 standard deviation of mean
like 95% of information lies between: "\\mu" - 2"\\sigma" to "\\mu" - 2"\\sigma"
So, On the available information
98.37 - 2(0.49) to 98.37 + 2(0.49)
97.39 to 99.35
So, 95% of information lies between 97.390F to 99.350F .
3) 99.7% of the information lies within 3 standard deviation of mean
like 99.7% of information lies between: "\\mu" - 3"\\sigma" to "\\mu" - 3"\\sigma"
So, On the available information
98.37 - 3(0.49) to 98.37 + 3(0.49)
96.90 to 99.84
So, 99.7% of information lies between 96.9°F to 99.84°F .
The approximate percentage of healthy adults with body temperatures within 2 standard deviations of the mean, or between 97.39°F to 99.35°F is 95%.
The approximate percentage of healthy adults with body temperatures between 97.88°F to 98.86°F is 68%.
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