Question #233784

The following table gives the average monthly exchange rate between the U.S. dollar and the euro for 2009. It shows that 1 euro was equivalent to 1.324 U.S. dollars in January 2009. Develop a trend line that could be used to predict the exchange rate for 2010. Use this model to predict the exchange rate for January 2010 and February 2010.

MONTH EXCHANGE RATE


1
Expert's answer
2021-09-09T00:13:56-0400
xy11.28921.32431.32141.31751.28061.25471.23081.24091.287101.298111.283121.311\def\arraystretch{1.5} \begin{array}{c:c} x & y \\ \hline 1 & 1.289 \\ \hdashline 2 & 1.324\\ \hdashline 3 & 1.321 \\ \hdashline 4 & 1.317\\ \hdashline 5 & 1.280 \\ \hdashline 6 & 1.254\\ \hdashline 7 & 1.230 \\ \hdashline 8 & 1.240\\ \hdashline 9 & 1.287 \\ \hdashline 10 & 1.298\\ \hdashline 11& 1.283 \\ \hdashline 12 & 1.311\\ \end{array}

xˉ=ixin=7812=6.5\bar{x}=\dfrac{\sum_ix_i}{n}=\dfrac{78}{12}=6.5

yˉ=iyin=15.43412=1.286167\bar{y}=\dfrac{\sum_iy_i}{n}=\dfrac{15.434}{12}=1.286167

SSxx=ixi21n(ix1)2=650112(78)2SS_{xx}=\sum_ix_i^2-\dfrac{1}{n}(\sum_ix_1)^2=650-\dfrac{1}{12}(78)^2

=143=143

SSyy=iyi21n(iy1)2=19.861426112(15.434)2SS_{yy}=\sum_iy_i^2-\dfrac{1}{n}(\sum_iy_1)^2=19.861426-\dfrac{1}{12}(15.434)^2

=0.010730=0.010730


SSxy=ixiyi1n(ix1)(iyi)SS_{xy}=\sum_ix_iy_i-\dfrac{1}{n}(\sum_ix_1)(\sum_iy_i)

=100.03112(78)(15.434)=0.291000=100.03-\dfrac{1}{12}(78)(15.434)=−0.291000

slope=m=SSxySSxx=0.291000143=0.002slope=m=\dfrac{SS_{xy}}{SS_{xx}}=\dfrac{−0.291000}{143}=-0.002

b=yˉmxˉ=1.286167(0.002)(6.5)b=\bar{y}-m\cdot\bar{x}=1.286167-(-0.002)(6.5)

=1.2994=1.2994

The equation of the trend line is


y=0.002x+1.2994y=-0.002x+1.2994



January 2010


y=0.002(13)+1.2994y=-0.002(13)+1.2994

y=1.273y=1.273

February 2010


y=0.002(14)+1.2994y=-0.002(14)+1.2994

y=1.271y=1.271

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