Question #233670

Suppose that the probabilities are 0.4, 0.3, 0.2, and 0.1, respectively, that 0, 1, 2, or 3 power failures will strike a certain subdivision in any given year. Find the mean and variance of the random variable X representing the number of power failures striking this subdivision.


Expert's answer

μ=Σi=14xip(xi)=0∗0.4+1∗0.3+2∗0.2+3∗0.1=1.\mu=\Sigma_{i=1}^4x_ip(x_i)=0*0.4+1*0.3+2*0.2+3*0.1=1.

σ2=Σi=14xi2p(xi)−μ2=02∗0.4+12∗0.3+22∗0.2+32∗0.1−12=1.\sigma^2=\Sigma_{i=1}^4x_i^2p(x_i)-\mu^2=0^2*0.4+1^2*0.3+2^2*0.2+3^2*0.1-1^2=1.


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