Question #228965

If sample mean = 54, sample standard deviation = 6, sample size = 25, confidence level = 90%, calculate the confidence interval for the estimate of the population mean.

Select one:

a. 51.95; 56.05

b. 54.8; 90.1

c. 50.6; 54.5

d. 6.0; 25.2


1
Expert's answer
2021-08-26T15:38:22-0400

M=54σ=6n=25M = 54 \\ \sigma = 6 \\ n=25

Two-sided confidence interval:

CI=(MZc×σn,M+Zc×σn)CI = (M - \frac{Z_c \times \sigma}{\sqrt{n}}, M + \frac{Z_c \times \sigma}{\sqrt{n}})

For 90 % confidence level

Zc=1.645CI=(541.645×625,54+1.645×625)=(541.974,54+1.974)=(52.026,55.974)Z_c=1.645 \\ CI = (54 - \frac{1.645 \times 6}{\sqrt{25}}, 54 + \frac{1.645 \times 6}{\sqrt{25}}) \\ =(54-1.974, 54+1.974) \\ = (52.026, 55.974)

There is no right option.


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