Question #227192

Let (\Omega , F, P) be a probability space and let E1 and E2 be two events with P(E₁) = 0.2, P(E₂) 0.4 and P(E₁/E₂)=0.1.


Find the probability that

(a) Exactly one of the events E1 or E₂ will occur.


(b) At least one of the events E1, or E2 will occur.


(c) None of E1 and E2 will occur


Expert's answer

(a)


P(Exactly one of the events E1 or E2)P(\text{Exactly one of the events }E_1\ or\ E_2)

=P(E1)P(E1E2)+P(E2)P(E1E2)=P(E_1)-P(E_1\cap E_2)+P(E_2)-P(E_1\cap E_2)

=0.20.1+0.40.1=0.4=0.2-0.1+0.4-0.1=0.4

(b)


P(At least one of the events E1 or E2)P(\text{At least one of the events }E_1\ or\ E_2)

=P(E1E2)=P(E1)+P(E2)P(E1E2)=P(E_1\cup E_2)=P(E_1)+P(E_2)-P(E_1\cap E_2)

=0.2+0.40.1=0.5=0.2+0.4-0.1=0.5

(c)


P(None of E1 and E2)P(\text{None of }E_1\ and\ E_2)

=1P(E1E2)=10.5=0.5=1-P(E_1\cup E_2)=1-0.5=0.5


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