Question #225667

A car manufacturer receives its air conditioning units from 3 different suppliers, A; B; C.

25% of its units come from supplier A, 26% from supplier B and 49% from supplier

C .It is known that 8% of the units from supplier A are defective, 8% of units from

supplier B are defective and 5% of units from supplier C is defective. If a unit is

selected at random and is found to be defective, what is the probability that it came

from Supplier A?


1
Expert's answer
2021-08-13T10:23:41-0400

probability of defective =came from A and defective+came from B and defective+came from C and defective

=0.25×0.08+0.26×0.08+0.49×0.05=0.02+0.0208+0.0245=0.0653= 0.25 \times 0.08 +0.26 \times 0.08 + 0.49 \times 0.05 \\ = 0.02 + 0.0208 + 0.0245 \\ = 0.0653

P(from A| defective) =0.5×0.080.0653=0.3062= \frac{0.5 \times 0.08}{0.0653}= 0.3062


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS