Question #225663

5. A jar contains black and white marbles. Two marbles are chosen without replacement.

The probability of selecting a black marble and then a white marble is 0.34, and the

probability of selecting a black marble on the first draw is 0.47. What is the probability

of selecting a white marble on the second draw, given that the first marble drawn was

black?


Expert's answer

P(White∣Black)=P(Black and White)P(Black)P(White|Black)=\dfrac{P(Black\ and\ White)}{P(Black)}

=0.340.47≈0.7234=\dfrac{0.34}{0.47}\approx0.7234

The probability of selecting a white marble on the second draw, given that the first marble drawn was

black is 0.7234.0.7234.



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