Solution
Given that,
"\\mu" = 0.517
"\\sigma" = 0.037
So,
"P(0.495 < x < 0.525)"
"P(\\frac{0.495-0.517}{0.037} < \\frac{x-\\mu}{\\sigma}<\\frac{0.525-0.517}{0.037})"
= "P(\\frac{-0.02}{0.037}<z<\\frac{0.01}{0.037})"
= "P(-0.54<z<0.27)"
= "P(z<0.27)-P(z<-0.54)"
= "0.6.64-0.2946"
= "0.3118"
= 31.18 %
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