Solution
Given that,
μ\muμ = 0.517
σ\sigmaσ = 0.037
So,
P(0.495<x<0.525)P(0.495 < x < 0.525)P(0.495<x<0.525)
P(0.495−0.5170.037<x−μσ<0.525−0.5170.037)P(\frac{0.495-0.517}{0.037} < \frac{x-\mu}{\sigma}<\frac{0.525-0.517}{0.037})P(0.0370.495−0.517<σx−μ<0.0370.525−0.517)
= P(−0.020.037<z<0.010.037)P(\frac{-0.02}{0.037}<z<\frac{0.01}{0.037})P(0.037−0.02<z<0.0370.01)
= P(−0.54<z<0.27)P(-0.54<z<0.27)P(−0.54<z<0.27)
= P(z<0.27)−P(z<−0.54)P(z<0.27)-P(z<-0.54)P(z<0.27)−P(z<−0.54)
= 0.6.64−0.29460.6.64-0.29460.6.64−0.2946
= 0.31180.31180.3118
= 31.18 %
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