The number of ways of randomly 2 loan "n\\left(S\\right)=10C_2=\\frac{10\\times 9}{2\\times 1}=\\frac{90}{2}=45"
The number of ways of selecting non - underwater loan "n\\left(E\\right)=\\left(10-3\\right)C_2=7C_2=\\frac{7\\times 6}{2\\times 1}=21"
"p\\left(E\\right)=Probability=\\frac{n\\left(E\\right)}{n\\left(S\\right)}=\\frac{21}{45}=\\frac{7}{15}"
The probability that neither of the selected loans is underwater is "\\frac{7}{15}" .
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