Question #221759

obtain the regression line (y=a+bx) from the following data

x: 5 9 1 10 5

y:7 10 3 8 2


Expert's answer

x‾=305=6,  y‾=305=6\overline{x}=\frac{30}{5}=6,\:\:\overline{y}=\frac{30}{5}=6

x‾=6 and y‾=6\overline{x}=6\:and\:\overline{y}=6


byx=n∑xy−∑x∑yn∑x2−(∑x2)=5(218)−(30×30)5(232)−232b_{yx}=\frac{n\sum xy-\sum x\sum y}{n\sum x^2-\left(\sum x^2\right)}=\frac{5\left(218\right)-\left(30\times 30\right)}{5\left(232\right)-232}


 byx=1090−9001160−232=190928=95464\:b_{yx}=\frac{1090-900}{1160-232}=\frac{190}{928}=\frac{95}{464}


Regression line yy on xx

 y−y‾=byx(x−x‾)\:y-\overline{y}=b_{yx}\left(x-\overline{x}\right)


y−6=95464(x−6)y-6=\frac{95}{464}\left(x-6\right)


464y−2784=95x−570464y-2784=95x-570


464y=95x+2214464y=95x+2214


464y=95x+2214464y=95x+2214


  y=2214464+95464x\:\:y=\frac{2214}{464}+\frac{95}{464}x


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