Question #221752

A random sample of size 20 is taken, resulting in a sample mean of 16.45 and

a sample standard deviation of 3.59. Assume x is normally distributed and use

this information and α=0.5 to test the following hypotheses. (use critical

t.025,19 = ±2.093)


Ho: μ = 16

Ha: μ 16


1
Expert's answer
2021-08-02T12:56:08-0400

In this case,

Samplemean=x=16.45Sample\:mean=\overline{x}=16.45


Samplestandarddeviation=s=3.59Sample\:standard\:deviation=s=3.59\:


Samplesize=n=20Sample\:size=n=20


Degreesoffreedom=19\:Degrees\:of\:freedom=19


Significancelevel=α=0.05Significance\:level=\alpha =0.05


Step 1: H0:μ=16H_0:\mu=16

H1:μ16H_1:\mu\:\:\not= \:16 (Two(Two tailedtailed test)test)

Step 2: Theteststatisticis,t=xμ(sn)The\:test\:statistic\:is,\:t=\frac{\overline{x}-\mu }{\left(\frac{s}{\sqrt{n}}\right)}\:

t=16.4516(3.5920)=0.5606t=\frac{16.45-16}{\left(\frac{3.59}{\sqrt{20}}\right)}=0.5606

Step 3: Pvalue=P(t>0.5606)=0.5816P-value=P\left(\left|t\right|>0.5606\right)=0.5816

Step 4: Conclusion: Since the PvalueP-value is greater than the significance level, we fail to reject HoH_o .


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