In this case,
Samplemean=x=16.45
Samplestandarddeviation=s=3.59
Samplesize=n=20
Degreesoffreedom=19
Significancelevel=α=0.05
Step 1: H0:μ=16
H1:μ=16 (Two tailed test)
Step 2: Theteststatisticis,t=(ns)x−μ
t=(203.59)16.45−16=0.5606
Step 3: P−value=P(∣t∣>0.5606)=0.5816
Step 4: Conclusion: Since the P−value is greater than the significance level, we fail to reject Ho .
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