A random sample of size 20 is taken, resulting in a sample mean of 16.45 and
a sample standard deviation of 3.59. Assume x is normally distributed and use
this information and α=0.5 to test the following hypotheses. (use critical
t.025,19 = ±2.093)
Ho: μ = 16
Ha: μ 16
In this case,
"Sample\\:mean=\\overline{x}=16.45"
"Sample\\:standard\\:deviation=s=3.59\\:"
"Sample\\:size=n=20"
"\\:Degrees\\:of\\:freedom=19"
"Significance\\:level=\\alpha =0.05"
Step 1: "H_0:\\mu=16"
"H_1:\\mu\\:\\:\\not= \\:16" "(Two" "tailed" "test)"
Step 2: "The\\:test\\:statistic\\:is,\\:t=\\frac{\\overline{x}-\\mu }{\\left(\\frac{s}{\\sqrt{n}}\\right)}\\:"
"t=\\frac{16.45-16}{\\left(\\frac{3.59}{\\sqrt{20}}\\right)}=0.5606"
Step 3: "P-value=P\\left(\\left|t\\right|>0.5606\\right)=0.5816"
Step 4: Conclusion: Since the "P-value" is greater than the significance level, we fail to reject "H_o" .
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