QUESTION 4
The time between customers arriving at a book store is exponentially distributed with a mean of 5
minutes.
(a) What is the probability that no customers arrive during a 30-minute period? (5)
(b) If the store opens at 9:00, what is the probability that the first customer of the day arrives
between 9:10 and 9:20? (6)
(c) If the store opens at 9:00, what is the probability that the first customer arrives at exactly
9:15? (4)
Suppose a random variable X denotes the time(in minutes) between customer's arrivals.
Therefore:
"X\\approx Exp\\left(\\lambda =\\frac{1}{5}=0.2\\right)"
"f\\left(x\\right)=\\lambda e^{-\\lambda x}\\:"
"f\\left(x\\right)\\:=0.2e^{-0.2x}\\:for\\:x\\ge 0"
(a). No customers arrive during a 30 - minute period if the the time between customer's arrivals is greater than 30 minutes.
Required probability is given by;
"P\\left(X>30\\right)=\\int _{30}^{\\infty }" "0.2e^{-0.2x}dx\\:"
"=\\left[-e^{-0.2x}\\:\\right]^{^{\\infty }}_{30}"
"=\\left[e^{-0.2x}\\:\\right]^{^{30\\:}}_{\\infty }"
"=e^{-0.2\\times 30}-e^{-\\infty }"
"=e^{-6}-0\\:"
"=0.0025"
Hence, "0.0025" is the probability that no customers arrive during a 30 - minute period.
(b). Considering 9:00 as the origin of time(i.e. time zero), we obtain 9:10 as 10 minutes and 9:20 as 20 minutes . Required probability is given by;
"P\\left(10<X<20\\right)=\\int _{10}^{20}0.2e^{-0.2x}\\:dx"
"=\\left[-e^{-0.2x}\\right]^{^{20}}_{10}"
"=\\left[e^{-0.2x}\\right]^{^{10}}_{20}"
"=e^{-0.2\\times 10}-e^{-0.2\\times 20}"
"=e^{-2}-e^{-4}\\:"
"=0.1353353-0.0183156"
"=0.1170"
Hence, "0.1170" is the probability that the first customer arrives between 9:10 and 9:20.
(c). Considering 9:00 as the origin of time (i.e. time zero), we obtain 9:15 as 15 minutes.
Required probability is given by;
"P\\left(X=15\\right)=\\int _{15}^{15}0.2e^{-0.2x}dx"
"=\\left[e^{-0.2x}\\right]^{^{15}}_{15}"
"=e^{-0.2\\times 15}-e^{-0.2\\times 25}"
"=e^{-3}-e^{-3}"
"=0.04978707-0.04978707"
"=0"
Hence, is the probability that the first customer arrives at exactly 9:15
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