Answer to Question #219944 in Statistics and Probability for reitu

Question #219944

QUESTION 4

The time between customers arriving at a book store is exponentially distributed with a mean of 5

minutes.

(a) What is the probability that no customers arrive during a 30-minute period? (5)

(b) If the store opens at 9:00, what is the probability that the first customer of the day arrives

between 9:10 and 9:20? (6)

(c) If the store opens at 9:00, what is the probability that the first customer arrives at exactly

9:15? (4)



1
Expert's answer
2021-07-25T17:12:35-0400

Suppose a random variable X denotes the time(in minutes) between customer's arrivals.

Therefore:

"X\\approx Exp\\left(\\lambda =\\frac{1}{5}=0.2\\right)"

"f\\left(x\\right)=\\lambda e^{-\\lambda x}\\:"

"f\\left(x\\right)\\:=0.2e^{-0.2x}\\:for\\:x\\ge 0"


(a). No customers arrive during a 30 - minute period if the the time between customer's arrivals is greater than 30 minutes.

Required probability is given by;


"P\\left(X>30\\right)=\\int _{30}^{\\infty }" "0.2e^{-0.2x}dx\\:"


"=\\left[-e^{-0.2x}\\:\\right]^{^{\\infty }}_{30}"


"=\\left[e^{-0.2x}\\:\\right]^{^{30\\:}}_{\\infty }"


"=e^{-0.2\\times 30}-e^{-\\infty }"


"=e^{-6}-0\\:"


"=0.0025"

Hence, "0.0025" is the probability that no customers arrive during a 30 - minute period.


(b). Considering 9:00 as the origin of time(i.e. time zero), we obtain 9:10 as 10 minutes and 9:20 as 20 minutes . Required probability is given by;


"P\\left(10<X<20\\right)=\\int _{10}^{20}0.2e^{-0.2x}\\:dx"


"=\\left[-e^{-0.2x}\\right]^{^{20}}_{10}"



"=\\left[e^{-0.2x}\\right]^{^{10}}_{20}"


"=e^{-0.2\\times 10}-e^{-0.2\\times 20}"


"=e^{-2}-e^{-4}\\:"


"=0.1353353-0.0183156"


"=0.1170"

Hence, "0.1170" is the probability that the first customer arrives between 9:10 and 9:20.


(c). Considering 9:00 as the origin of time (i.e. time zero), we obtain 9:15 as 15 minutes.

Required probability is given by;

"P\\left(X=15\\right)=\\int _{15}^{15}0.2e^{-0.2x}dx"


"=\\left[e^{-0.2x}\\right]^{^{15}}_{15}"


"=e^{-0.2\\times 15}-e^{-0.2\\times 25}"


"=e^{-3}-e^{-3}"


"=0.04978707-0.04978707"


"=0"

Hence, is the probability that the first customer arrives at exactly 9:15

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