Solution:
Given, p=60%=0.6,n=50p=60\%=0.6, n=50p=60%=0.6,n=50
Mean=μ=np=0.6×50=30Variance=σ2=np(1−p)=0.6(50)(0.4)=12Mean=\mu=np=0.6\times50=30 \\Variance=\sigma^2=np(1-p)=0.6(50)(0.4)=12Mean=μ=np=0.6×50=30Variance=σ2=np(1−p)=0.6(50)(0.4)=12
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments