Product table
Total number of outcomes = 36
1. A = the product will be 5
A ={(1,5), (5,1)}
n(A)=2
"P(A) = \\frac{2}{36}= \\frac{1}{18}"
2. B= the product will be at most 6
B= {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (3,1), (3,2), (4,1), (5,1), (6,1)}
n(B) = 14
"P(B) = \\frac{14}{36} = \\frac{7}{18}"
3. C= the product will be at least 7
C={(2,4), (2,5), (2,6),
(3,3), (3,4), (3,5), (3,6),
(4,2), (4,3), (4,4), (4,5), (4,6),
(5,2), (5,3), (5,4), (5,5), (5,6),
(6,2), (6,3), (6,4), (6,5), (6,6)}
n(C) = 22
"P(C) = \\frac{22}{36} = \\frac{11}{18}"
4. D= the product will be a square number
D={(1,1), (1,4), (2,2), (3,3), (4,1), (4,4), (5,5), (6,6)}
n(D) = 8
"P(D) = \\frac{8}{36}= \\frac{2}{9}"
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