Question #215484

A project yields an average cash-flow of Rs. 400 lakh with a standard deviation of Rs. 60 lakh. Calculate the following probabilities: (i) Cash flow will be more than Rs. 550 lakh (ii) Cash flow will be between Rs. 450 lakh and Rs. 520 lakh.


1
Expert's answer
2021-07-12T16:47:39-0400

Let X=X= cash flow: XN(μ,σ2).X\sim N(\mu, \sigma^2).

Given μ=400,σ=60.\mu=400, \sigma=60.

(i)


P(X>550)=1P(X550)P(X>550)=1-P(X\leq 550)

=1P(Z55040060)=1-P(Z\leq \dfrac{550-400}{60})

=1P(Z2.5)=1-P(Z\leq 2.5)

0.0062\approx0.0062

(ii)


P(450<X<520)=P(X<520)P(X450)P(450<X<520)=P(X<520)-P(X\leq 450)

=P(Z<52040060)P(Z45040060)=P(Z< \dfrac{520-400}{60})-P(Z\leq \dfrac{450-400}{60})

=P(Z<2)P(Z0.8333)=P(Z<2)-P(Z\leq 0.8333)

0.977250.797670.1796\approx0.97725-0.79767\approx0.1796


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