Answer to Question #211007 in Statistics and Probability for Hammad

Question

A fair dice is cast what’s the probability that

(a)the result is 4

(b)the result is odd

Answer 1

(a) Since the dice has 6 faces, the total number of outcomes is n=6.

Of all the outcomes, only m = 1 suits us. So, the wanted probability is $p = \frac{m}{n} = \frac{1}{6}$ .

Answer: $p = \frac{1}{6}$

(b) Likewise, the total number of outcomes is n=6.

The number of favorable outcomes is m=3 (1, 3 and 5 points).

So, the wanted probability is $p =\frac{1}{2}$ .

Answer: $p =\frac{1}{2}$