A bag contains four $5 bills, five $10 bills and three $20 bills. two bills
are selected without the first selection being replaced find P($5 then
$5)
Solution:
Number of $5 bills = 4
Number of $10 bills = 5
Number of $20 bills = 3
Total bills = 4+5+3 = 12
P($5 then $5) = P($5) x P($5)
"=\\dfrac{4}{12} \\times \\dfrac{3}{11} = \\dfrac{1}{11}"
Comments
Leave a comment