Let X= life of a power station: X∼Exp(λ).
μ=30=>λ=μ1=301
1.
P(X≤50)=1−e−301(50)=1−e−35≈0.8112
The chance that the power station is inoperative is 0.8112.
2.
P(X≥40)=1−P(X<40)=1−(1−e−301(40))=e−34≈0.8112
=e−34≈0.2636 Let Y= the number of lamps working after 40 years: Y∼Bin(n,p).
p=0.2636,n=6,q=1−p=1−0.2636=0.7364
P(Y≥4)=P(Y=4)+P(Y=5)+P(Y=6)
=(46)(0.2636)4(0.7364)2+(56)(0.2636)5(0.7364)1
+(66)(0.2636)6(0.7364)0≈0.045232The chance that at least 4 from 6 power stations will still stand after 40 years is 4.5%.
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