Solution:
Given, μ=1.9,σ=0.3
X∼N(μ,σ)
(i):
P(1.5<X<2)=P(X<2)−P(X<1.5)=P(z<0.32−1.9)−P(z<0.31.5−1.9)=P(z<0.33)−P(z<−1.33)=P(z<0.33)−[1−P(z<1.33)]=0.62930−[1−0.90824]=0.53754
(ii):
P(X>2.4)=1−P(X≤2.4)=1−P(z≤0.32.4−1.9)=1−P(z≤1.67)=1−0.95254=0.04746
(iii):
P(X<x)=0.94⇒P(z<0.3x−1.9)=0.94⇒0.3x−1.9=1.55⇒x=2.365
Required length of movie is 2.365 hours.
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