The mean weight of loads of rock is 47.0 tons with a standard deviation of 6.0 tons. If 16 loads are chosen at random for a weight check, find the probability that the mean weight of those loads is less than 46.2 tons. Assume that the variable is normally distributed.
"\\mu = 47.0 \\\\\n\n\\sigma=6.0 \\\\\n\nn=16 \\\\\n\nP(\\bar{X}<46.2) = P(Z< \\frac{46.2-47}{6.0\/ \\sqrt{16}} )\\\\\n\n= P(Z< -0.533) \\\\\n\n= 0.2970"
Comments
Leave a comment