Question #207752

A. Use the z-table to find the area that corresponds to each of the following:

1. z = 0.67

2. z = − 1.5

3. z = .78

4. z = − 2.35

5. z = 1.8

B. Given = 62 and = 8. Find the z-score value that corresponds to each of the following scores.

1. X = 50

2. X = 78

3. X = 82

Find the raw score that corresponds to each of the following.

4. = 8, = 52, z = − 1.5

5. = 15, = 75, z = 0.47

C. Solving Problem.

1. The length of human pregnancies from conception to birth approximates a normal 

distribution with a mean of 266 days and a standard deviation of 16 days. What 

probability/proportion of all pregnancies will last between 240 and 270 days (roughly 

between 8 and 9 months)?

2. The result of a nationwide aptitude test in mathematics are normally distributed with = 80 

and = 15. 

a. What is the percentile rank of a score of 87?

b. What is the score that corresponds to a percentile rank of 94.5%?


1
Expert's answer
2021-06-17T14:11:32-0400

A.

1. P(z<0.67)=0.7486P(z<0.67)=0.7486


2. P(z<1.5)=0.0668P(z<-1.5)=0.0668


3. P(z<0.78)=0.7823P(z<0.78)=0.7823


4. P(z<2.35)=0.0094P(z<-2.35)=0.0094


5. P(z<1.8)=0.9641P(z<1.8)=0.9641


B.

1. z=50628=1.5z=\dfrac{50-62}{8}=-1.5


2. z=78628=2z=\dfrac{78-62}{8}=2


3. z=82628=2.5z=\dfrac{82-62}{8}=2.5


4. x=μ+zσ=521.5(8)=40x=\mu+z\sigma=52-1.5(8)=40


5. x=μ+zσ=75+0.47(15)=82.05x=\mu+z\sigma=75+0.47(15)=82.05


C.

1.

P(240<X<270)=P(X<270)P(X240)P(240<X<270)=P(X<270)-P(X\leq240)

=P(Z<27026616)P(Z24026616)=P(Z<\dfrac{270-266}{16})-P(Z\leq\dfrac{240-266}{16})

=P(Z<0.25)P(Z1.625)=P(Z<0.25)-P(Z\leq-1.625)

0.598710.052080.5466,54.66%\approx0.59871-0.05208\approx0.5466, 54.66\%

2.

a.


P(X<87)=P(Z<878015)P(X<87)=P(Z<\dfrac{87-80}{15})

P(Z<0.46667)0.6796\approx P(Z<0.46667)\approx0.6796

0.598710.052080.5466,54.66%\approx0.59871-0.05208\approx0.5466, 54.66\%

b.

P(Z<z)=0.945P(Z<z)=0.945

z1.59821.6z\approx1.5982\approx1.6

x80+1.5982(15)103.973104x\approx80+1.5982(15)\approx103.973\approx104


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