There are 63=216 outcomes for rolling three fair dices together.
Suitable outcomes
(1,1,5),(1,1,6),(1,3,5),(1,3,6),
(3,1,5),(3,1,6),(3,3,5),(3,3,6),
(5,1,5),(5,1,6),(5,3,5),(5,3,6)The probability of the event "odd number on first and 1 or 3 on second, and 5 or 6 on third" is
P(I∩II∩III)=21612=181 The probability of the event "odd number on first" is
P(I)=63=21 The probability of the event "1 or 3 on second" is
P(II)=62=31 The probability of the event "5 or 6 on third" is
P(III)=62=31 Hence
P(I)P(II)P(III)=21(31)(31)=P(I∩II∩III) The events are independent.
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