Assuming we're working in base ten, the digits in question are 0,1,2,3,4,5,6,7,8,9.
Suppose we take a group of k digits, d1,d2,...,dk.
What is the probability that d1=0 ?
P1(d1=0)=109
P2(d1,d2=0)=109(109)=(109)2
...
Pk(d1,d2,...,dk=0)=(109)k The probabilty that doesn't appear among k digits chosen indepentantly and uniformy at random is (109)k .
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