Question #205422

what is the probabilty that 0 doesnt appear among k digits chosen indepentantly and uniformy at random


Expert's answer

Assuming we're working in base ten, the digits in question are 0,1,2,3,4,5,6,7,8,9.0,1,2,3,4,5,6,7,8,9.

Suppose we take a group of kk digits, d1,d2,...,dk.d_1,d_2,...,d_k.

What is the probability that d1≠0d_1\not=0 ?


P1(d1≠0)=910P_1(d_1\not=0)=\dfrac{9}{10}




P2(d1,d2≠0)=910(910)=(910)2P_2(d_1,d_2\not=0)=\dfrac{9}{10}(\dfrac{9}{10})=(\dfrac{9}{10})^2

......

Pk(d1,d2,...,dk≠0)=(910)kP_k(d_1,d_2,...,d_k\not=0)=(\dfrac{9}{10})^k

The probabilty that doesn't appear among kk digits chosen indepentantly and uniformy at random is (910)k(\dfrac{9}{10})^k .



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