Question #205149

.A certain federal agency employs three consulting firms (A, B and C) with probabilities 0.4, 0.35, 0.25, respectively. From past experience, it is known that the probabilities of cost overrun for the firms are 0.05, 0.03, and 0.15 respectively. Suppose a cost overrun is experienced by the agency. a) What is the probability that the consulting firm involved is company C? b) What is the probability that it is company A?


1
Expert's answer
2021-06-18T09:22:27-0400

Solution:

It is given:

P(A)=0.4

P(B)=0.35

P(C)=0.25

Let L denotes the event that the company experience cost overrun.

It is given:

P(L | A)=0.05

P(L | B)=0.03

P(L | C)=0.15

a) We find the probability that the consulting firm involved is company C, i.e. we need to find P(CL)P(C \mid L) .

Using Bayes' theorem, we get the required probability :

P(CL)=P(LC)P(C)P(LC)P(C)+P(LB)P(B)+P(LA)P(A)=0.150.250.150.25+0.030.35+0.050.4=0.03750.0680.551\begin{aligned} P(C \mid L) &=\frac{P(L \mid C) P(C)}{P(L \mid C) P(C)+P(L \mid B) P(B)+P(L \mid A) P(A)} \\ &=\frac{0.15 \cdot 0.25}{0.15 \cdot 0.25+0.03 \cdot 0.35+0.05 \cdot 0.4} \\ &=\frac{0.0375}{0.068} \\ & \approx 0.551 \end{aligned}

b) We find the probability that the consulting firm involved is company A, i.e. we need to find P(AL)P(A \mid L) .

Using Bayes' theorem, we get the required probability :


P(AL)=P(LA)P(A)P(LC)P(C)+P(LB)P(B)+P(LA)P(A)=0.050.40.150.25+0.030.35+0.050.4=0.020.0680.294\begin{aligned} P(A \mid L) &=\frac{P(L \mid A) P(A)}{P(L \mid C) P(C)+P(L \mid B) P(B)+P(L \mid A) P(A)} \\ &=\frac{0.05 \cdot 0.4}{0.15 \cdot 0.25+0.03 \cdot 0.35+0.05 \cdot 0.4} \\ &=\frac{0.02}{0.068} \\ & \approx 0.294 \end{aligned}


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