Answer to Question #203973 in Statistics and Probability for zainab

Question #203973

We wish to estimate the mean serum indirect bilirubin level of 4-day-old infants. The mean for a sample of 16 infants was found to be 5.98 mg100 cc. Assume that bilirubin levels in 4-day-old infants are approximately normally distributed with a standard deviation of 3.5 mg100 cc.


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Expert's answer
2021-06-07T14:39:37-0400

n=16xˉ=5.98s=3.5H0:μ=4H1:μ>4n=16 \\ \bar{x}= 5.98 \\ s=3.5 \\ H_0: \mu= 4 \\ H_1: \mu > 4

Test statistic:

t=xˉμs/n=5.9843.5/16=2.2629t = \frac{\bar{x}- \mu}{s / \sqrt{n}} \\ = \frac{5.98-4}{3.5 / \sqrt{16} } \\ = 2.2629

p-value = 0.01945

p-value<0.05

Reject H0.

It is concluded that, population mean is greater than 4.

The 95 % confidence interval for the population mean:

Z0.05/2=1.96CI=xˉ±Z0.05/2×sn=5.98±1.96×3.516=5.98±1.715(4.265,7.695)Z_{0.05/2}=1.96 \\ CI = \bar{x}±Z_{0.05/2} \times \frac{s}{\sqrt{n}} \\ = 5.98 ±1.96 \times \frac{3.5}{\sqrt{16}} \\ = 5.98 ± 1.715 \\ (4.265, 7.695)


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