Question #202515

A traffic engineer records a sample of the types of vehicles that cross a bridge. she counts 112 passenger cars, 18 light trucks, and 20 heavy trucks. she wants to make a spinner to model the probability of each type of vehicle crossing the bridge. Determine the percent of each sector of the spinner to the nearest percent. To the nearest tenth of a percent, what is the probability that at a given moment, a light truck crosses the bridge followed by a heavy truck?


1
Expert's answer
2021-06-03T17:18:34-0400

112+18+20=150112 + 18 + 20 = 150 total vehicles


112150=0.746=74.6%\frac{112}{150 }= 0.746 = 74.6\% rounds to 75% passenger cars

18150=0.12=12%\frac{18}{150} = 0.12 = 12\% light trucks

20150=0.133=13.3%\frac{20}{150} = 0.133 = 13.3\% rounds to 13% heavy trucks


P(light truck followed by heavy truck)=18150×20149=12745= \frac{18}{150} \times \frac{20}{149} =\frac { 12}{745 } or 1.6%


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS