In a survey of men in the United
States (ages 20-29), the mean height was 69.6 inches with a standard deviation of 3.0 inches. Find the minimum height in the top 16%.
"\\mu=69.6 \\\\\n\n\\sigma=3.0 \\\\\n\nP(X>x) = 0.16 \\\\\n\nP(X<x) = 1-0.16 = 0.84 \\\\\n\nP(Z< \\frac{x-\\mu}{\\sigma}) = 0.84 \\\\\n\n\\frac{x-69.6}{3.0}=0.995 \\\\\n\nx-69.6= 3.0 \\times 0.995 \\\\\n\nx = 69.6+2.985 = 72.585"
Answer: 72.58 inches
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