Answer to Question #202124 in Statistics and Probability for Ali raza

Question

An integer between 5 and 40 (both exclu Suppose sive) is chosen at random. What is the probability that 

i. It is an odd number?

ii. It is an even number and divisible by 4.

Answer 1

i. In total, we have 34 integers from 5 to 40, so n=5.

The number of odd numbers from 5 to 40 is m=17

Then the wanted probability is $p = \frac{m}{n} = \frac{{17}}{{34}} = \frac{1}{2}$

Answer: $p = \frac{1}{2}$

ii. The number of even numbers divisible by 4 in the range from 5 to 40 is m=8, so

$p = \frac{m}{n} = \frac{{8}}{{34}} = \frac{4}{17}$

Answer: $p =\frac{4}{17}$