Suppose that the time required to complete a 1040R tax form is normally distributed with a mean of 100 minutes and a standard deviation of 20 minutes. What proportion of 1040R tax forms will be completed in more than 127 minutes? Round your answer to at least four decimal places.
"\\mu=100,\\sigma=20"
Proportion of 1040R tax forms will be completed in more than 127 minutes-
"P(X>127)=P(z>\\dfrac{127-100}{20})=P(z>\\dfrac{27}{20})=P(z>1.35)=0.0885"
Hence The proportion is 8.85%.
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