Question #187555

 A chord connecting two points randomly chosen on a circunference of a disk of radius 1 cuts it into two segments. Select the best approximation to the mathematical expectation of the area of the smaller segment.

1. O.2

2. 0.6

3. 0.4

4 0. 8

5. 1


1
Expert's answer
2021-05-07T11:18:02-0400

Let the circle of centre O and radius 1 unit . A and B are two points on the circumference which cuts the circle into two segments. The portion under AB is a minor segment.



Area of smaller segment = Area of sector AOB - Area of Triangle AOB

Area of sector AOB for angle θ\theta =θ×πr2360= \theta \times \dfrac{\pi r^2}{360}


Area of Triangle AOB =12×base×height.= \dfrac{1}{2} \times base \times height.


=12×OA×BM= \dfrac{1}{2} \times OA \times BM


=12×r×rsinθ=12r2sinθ= \dfrac{1}{2} \times r \times rsin\theta = \dfrac{1}{2}r^2sin\theta


Area of smaller segment =θπr236012r2sinθ= \dfrac{\theta \pi r^2}{360}- \dfrac{1}{2}r^2sin \theta


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