Question #185117

A lottery that pays off Php 300 000. 00 is made available for 10 000 000 tickets. Each ticket costs Php 50.00. Suppose the variable X gives the net winnings from paying lottery. What is the expected gain for joining the lottery with only one ticket?


Expert's answer

The probability that the ticket is winning (net winnings are equal to 300000000-50 = 299999950) is p1=110000000{p_1} = \frac{1}{{10000000}}

The probability that a ticket without a win (net win is -50) is p2=10000000−110000000=999999910000000{p_2} = \frac{{10000000 - 1}}{{10000000}} = \frac{{{\rm{9999999}}}}{{10000000}}

We have a distribution series

xi299999950−50pi110000000999999910000000\begin{matrix} {{x_i}}&{299999950}&{ - 50}\\ {{p_i}}&{\frac{1}{{10000000}}}&{\frac{{{\rm{9999999}}}}{{10000000}}} \end{matrix}

Then the expected gain is

M(x)=∑xipi=299999950⋅1−50⋅999999910000000=−20M(x) = \sum {{x_i}{p_i}} = \frac{{299999950 \cdot 1 - 50 \cdot {\rm{9999999}}}}{{10000000}} = -20

Answer: -20 pesos


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