Let the population be given by the numbers. Take all random samples of size 3 without replacement and obtain the sampling distribution of the sample mean
Let the population consists of numbers 15,9,24,615,9,24,615,9,24,6 and 181818 .
Sampling distribution of size 3 can be given as
Sampling distribution of Sample mean,
P(Xˉ=16)=310P(\bar X = 16) = \dfrac{3}{10}P(Xˉ=16)=103
P(Xˉ=15)=110P(\bar X = 15) = \dfrac{1}{10}P(Xˉ=15)=101
P(Xˉ=19)=310P(\bar X = 19) = \dfrac{3}{10}P(Xˉ=19)=103
P(Xˉ=13)=110P(\bar X = 13) = \dfrac{1}{10}P(Xˉ=13)=101
P(Xˉ=11)=110P(\bar X = 11) = \dfrac{1}{10}P(Xˉ=11)=101
P(Xˉ=14)=110P(\bar X = 14) = \dfrac{1}{10}P(Xˉ=14)=101
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments