Answer to Question #184466 in Statistics and Probability for Jessie Wall

Question

Data collected from a website show that 60% of visitors you scavenger as their web browser you randomly select 100 visitors from the website and record how many you scavenger for any single visitor what is the probability that they do not use scavenger

Answer 1

From the given question we know that 60% use scavenger as their web browser.

Hence, Probability that visitors use scavenger as their web browser = 0.6

We have 100 visitor

Using binomial distribution.

$P(x) = ^{100}C_x(0.6)^x(0.4)^{100-x}$

Probability that all 100 visitors use scavenger

$= P(100) = ^{100}C_{100}(0.6)^{100}(0.4)^{100-100}$

Hence,

Probability that they do not use scavenger $= 1 - ^{100}C_{100}(0.6)^{100}$

= $1-(0.6)^{100}$