Find the mean of the probability distribution of the random variable X if P(X) = (2X-1)/10 for X=1,2,3,4, and 5
We subsitute XXX and receive: P(X=1)=1/10;P(X=2)=3/10;P(X=1)=1/10;\quad P(X=2)=3/10;P(X=1)=1/10;P(X=2)=3/10;
P(X=3)=5/10P(X=3)=5/10P(X=3)=5/10; P(X=4)=7/10;P(X=5)=9/10.P(X=4)=7/10;\quad P(X=5)=9/10.P(X=4)=7/10;P(X=5)=9/10.
As we can see, it is not a distribution, since the sum of all probabilities is greatet than 1. E.g., P(X=4)+P(X=5)=16/10>1.P(X=4)+P(X=5)=16/10>1.P(X=4)+P(X=5)=16/10>1.
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