If You buy one ticket the expected gain is x.
There are two possibilities:
lose → x=0 (nothing gain)
win → x = 2000 gain
The expected value μ is the sum of the product of each possibility x with its probability P(x):
"E(x) = \u03bc = \\sum xP(X) \\\\\n\n= 0 + \\frac{2000}{400} \\\\\n\n= 5"
The expected value is 5.
The variance is the expected value of the squared deviation from the mean:
"\u03c3^2 = \\sum (x- \u03bc)^2P(x) \\\\\n\n= (0-5)^2 \\times \\frac{399}{400} + (2000-5)^2 \\times \\frac{1}{400} \\\\\n\n= 24.93+4.98 \\\\\n\n= 29.91"
The variance is 29.91.
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