A researcher performs three independent hypothesis tests each at the 5% significance level.
Determine the probability of observing at LEAST one Type I Error. (Round your final answer to the nearest hundredth of a percent)
x ~ Binomial (3, 0.05)
The binomial distribution function.
"P(x=k) = ^nC^k(p^k)(1 \u2013 p)^{n-k} \\\\\n\nP(x\u22651) = 1 -P(x=0) \\\\\n\n= 1 -^3C^0(0.05)^0(0.95)^3 \\\\\n\n= 1 -0.8573 \\\\\n\n= 0.1427"
Answer: 14.27 %
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