Five hundred children participated in a field demonstration. Their heights averaged is 110 cm with a standard deviation of 6 cm. What is the probability that the height of a child, picked at random, is greater than 104 cm?
Here the everage heights of the "500" children is "110" cm with standard deviation "6" cm.
Let "X" be a random variable denotes the height of the students.
Then "X" is normally distributed with mean "110" cm and standard deviation "6" cm.
Therefore we have "\\mu =110" and "\\sigma=6" .
Let us take "Z= \\frac{X-\\mu}{\\sigma}" . Then "Z=\\frac{X-110}{6}".
Now we have to find "P(X>104)."
"\\therefore P(X>104)=P(Z>\\frac{104-110}{6})"
"=P(Z>-1)"
"=0.5+P(0\\leq Z\\leq 1)"
"=0.5+0.3413" [ from normal distribution table ]
"=0.8413"
Which is the required probability.
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