Suppose three laptops are tested.Let D represent the defective laptop and N for the non defective laptops.how many possible outcomes will occur from the experiment and what are the possible values of the random variable?
We want to find out the number of defective cellphones that occur in the test.
After testing the cell phones we can receive 4 types of result:
1) In case 1 all cell phones are working. So we have 0 cell phones that donโt work and ๐ has a value 0.
2) In case 2 only one of the phones is broken and the others are good. Then ๐ has value 1.
3) In case 3 we have two broken cellphones and one working cellphone. So ๐ has value 2.
4) In case 4 all three cellphones are defective. ๐ has a value 3
After analysis of all possible cases, we receive that ๐ may be equal to 0, 1, 2, or 3.
Distribution law for ๐:
Here "p_i" stands for probability of the ๐-th case and
Answer: ๐ โ {0,1,2,3}.
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