A factory producing 50,000 pairs of shoes daily. From a sample of 500 pairs 2% were found to be substandard quality. Estimate the number of pairs that can be reasonably expected to be spoiled in the daily production and assign limits at 95% level of confidence.
Determination of Confidence Limit For Population Proportion
Because you want a 95% confidence interval, your z-value is 1.96.
From a sample of 500 pairs 2% were found to be substandard quality. So
"\\hat{p} =2 \\; \\%=0.02"
The formula for a confidence interval for a population proportion is
"\\hat{p}\u00b1z \\times \\sqrt{\\frac{\\hat{p}(1- \\hat{p})}{n}}"
Find
"\\hat{p}\\frac{1 - \\hat{p}}{n} = 0.02 \\frac{1-0.02}{500} = 3.92 \\times 10^{-5}"
Take the square root to get 0.00626
Multiply your answer by z.
This step gives you the margin of error.
"1.96 \\times 0.00626 = 0.0122"
Confidence interval:
0.02±0.012 or (0.008, 0.032)
The number of pairs that can be reasonably expected to be spoiled in the daily production:
"50000 \\times 0.02 \u00b1 50000 \\times 0.012" or "(50000 \\times 0.008, 50000 \\times 0.032)"
1000 ± 600 or (400, 1600)
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