Question #171928

A factory producing 50,000 pairs of shoes daily. From a sample of 500 pairs 2% were found to be substandard quality. Estimate the number of pairs that can be reasonably expected to be spoiled in the daily production and assign limits at 95% level of confidence.


1
Expert's answer
2021-03-17T10:55:44-0400

Determination of Confidence Limit For Population Proportion

Because you want a 95% confidence interval, your z-value is 1.96.

From a sample of 500 pairs 2% were found to be substandard quality. So

p^=2  %=0.02\hat{p} =2 \; \%=0.02

The formula for a confidence interval for a population proportion is

p^±z×p^(1p^)n\hat{p}±z \times \sqrt{\frac{\hat{p}(1- \hat{p})}{n}}

Find

p^1p^n=0.0210.02500=3.92×105\hat{p}\frac{1 - \hat{p}}{n} = 0.02 \frac{1-0.02}{500} = 3.92 \times 10^{-5}

Take the square root to get 0.00626

Multiply your answer by z.

This step gives you the margin of error.

1.96×0.00626=0.01221.96 \times 0.00626 = 0.0122

Confidence interval:

0.02±0.012 or (0.008, 0.032)

The number of pairs that can be reasonably expected to be spoiled in the daily production:

50000×0.02±50000×0.01250000 \times 0.02 ± 50000 \times 0.012 or (50000×0.008,50000×0.032)(50000 \times 0.008, 50000 \times 0.032)

1000 ± 600 or (400, 1600)


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