Five hundred children participated in a field demonstration. Their heights averaged 110
cm with a standard deviation of 6 cm.
The probability that X<104 is equal to the blue area under the curve.

Since μ=110 and σ=6 we have:
P(X<104)=P(X−μ<104−110)=P(σX−μ<6104−110)
Since
σx−μ=Z and 6104−110=−1
we have:
P(X<104)=P(Z<−1)
Use the standard normal table to conclude that:
P(Z<−1)=0.1587
Answer: 0.1587.