What is the probability that the shelf life of the battery is between 400 days and 550 days?
A certain type of battery has a mean shelf life of 600 days with a standart deviation of 28 days.
The probability that 400<X<550 is equal to the blue area under the curve.
Since "\\mu=600" and "\\sigma=28" we have:
"P(400<X<550) = P(400-600<X-\\mu<550-600)\\\\=P(\\frac{400-600}{28}<\\frac{X-\\mu}{\\sigma}<\\frac{550-600}{28})"
Since
"\\frac{x-\\mu}{\\sigma} = Z" , "\\frac{400-600}{28} = -7.14" and "\\frac{550-600}{28} = -1.79" we have:
"P(400<X<550)=P(-7.14<Z<-1.79)"
Use the standard normal table to conclude that:
"P(-7.14<Z<-1.79)=P(-1.79)-P(-7.14)=0.03673-0=0.03673"
Answer: 0.0367.
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