A certain type of battery has a mean shelf life of 600 days with a standart deviation of 28 days.
The probability that 400<X<550 is equal to the blue area under the curve.
Since μ=600 and σ=28 we have:
P(400<X<550)=P(400−600<X−μ<550−600)=P(28400−600<σX−μ<28550−600)
Since
σx−μ=Z , 28400−600=−7.14 and 28550−600=−1.79 we have:
P(400<X<550)=P(−7.14<Z<−1.79)
Use the standard normal table to conclude that:
P(−7.14<Z<−1.79)=P(−1.79)−P(−7.14)=0.03673−0=0.03673
Answer: 0.0367.
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