p=0.1⇒q=1−p=0.9
Using the Bernoulli formula, we find the probabilities that there will be 0, 1, 2, 3, 4, 5 and 6 bad eggs, respectively:
P6(0)=q6=0.96=0.531441
P6(1)=C61pq5=6⋅0.1⋅0.95=0.354294
P6(2)=C62p2q4=15⋅0.12⋅0.94=0.098415
P6(3)=C63p3q3=20⋅0.13⋅0.93=0.01458
P6(4)=C64p4q2=15⋅0.14⋅0.92=0.001215
P6(5)=C65p5q=6⋅0.15⋅0.9=0.000054
P6(6)=p6=0.16=0,000001
We have the probability distribution:
Xp00.53144110.35429420.09841530.0145840.00121550.00005460,000001
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