Answer to Question #167477 in Statistics and Probability for kibe

Question #167477

The Dean the School of education in a University wants to determine whether there are statistically significant difference of opinion among the different cadres of academic staff members at the university concerning a proposed curriculum change in which postgraduate students are to be taught research methods on-line. Interviewing a sample of 313 members of the academic staff constituting 104 Lecturers, 131 Senior Lecturers, and 78 Professors, the Dean obtained the results shown in the following table:

 

Rank

 

Response

Lecturer

Senior Lecturer

Professor

Total

Against

47

34

14

95

Not committed

41

49

29

119

In support

16

48

35

99

Total

104

131

78

313

 

Compute a chi-square test for the above data and draw conclusion at α = .05                              

           

4) The mean I.Q of a sample of 1600 children was 99. It is likely that this was a random sample from a population with mean I.Q 100 and standard deviation 15.

 Required:

Using appropriate statistics, deduce whether there is any statistically significant difference between the two means if z critical value at α = .05 is 1.96                                                        



1
Expert's answer
2021-03-03T07:14:09-0500


There is statistically significant difference of opinion among the different cadres of academic staff members.

"4)\\ N=1600\\\\\n\\overline{x}=99\\\\\na_0=100\\\\\n\\sigma=15\\text{ --- population standard deviation.}\\\\\n\\alpha=0.05\\\\\nH_0:a=a_0=100\\\\\nH_1:a\\neq a_0=100\\\\\na\\text{ --- population mean}.\\\\\n\\text{We will use the following random variable}:\\\\\nU=\\frac{(\\overline{X}-a_0)\\sqrt{n}}{\\sigma}\\\\\n\\text{Observed value }u_{obs}=\\frac{(99-100)\\sqrt{1600}}{15}\\approx -2.7\\\\\n\\text{Critical value } u_{cr}:\\\\\n\\Phi(u_{cr})=\\frac{1-\\alpha}{2}\\\\\n\\Phi(u_{cr})=0.475\\\\\nu_{cr}\\approx 1.96\\\\\n\\Phi(x)=\\frac{1}{\\sqrt{2\\pi}}\\int_0^xe^{-\\frac{t^2}{2}}dt\\text{ --- Laplace function}.\\\\\n\\text{Critical region}: (-\\infty,-1.96)\\cup (1.96,\\infty)\\\\\nu_{obs}\\approx -2.7 \\text{ is in the critical region. So we reject }H_0\\\\\n\\text{and accept }H_1."


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